4x+y^2-3z^2+1=0

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Solution for 4x+y^2-3z^2+1=0 equation: 


Simplifying
4x + y2 + -3z2 + 1 = 0

Reorder the terms:
1 + 4x + y2 + -3z2 = 0

Solving
1 + 4x + y2 + -3z2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 4x + y2 + -1 + -3z2 = 0 + -1

Reorder the terms:
1 + -1 + 4x + y2 + -3z2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4x + y2 + -3z2 = 0 + -1
4x + y2 + -3z2 = 0 + -1

Combine like terms: 0 + -1 = -1
4x + y2 + -3z2 = -1

Add '-1y2' to each side of the equation.
4x + y2 + -1y2 + -3z2 = -1 + -1y2

Combine like terms: y2 + -1y2 = 0
4x + 0 + -3z2 = -1 + -1y2
4x + -3z2 = -1 + -1y2

Add '3z2' to each side of the equation.
4x + -3z2 + 3z2 = -1 + -1y2 + 3z2

Combine like terms: -3z2 + 3z2 = 0
4x + 0 = -1 + -1y2 + 3z2
4x = -1 + -1y2 + 3z2

Divide each side by '4'.
x = -0.25 + -0.25y2 + 0.75z2

Simplifying
x = -0.25 + -0.25y2 + 0.75z2

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